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    Paediatrics and maternity proctored exam (examplify)
    Calculation

    A client underwent genetic testing and found out that they are heterozygous for the Huntington's disease gene, an autosomal dominant disorder. Their partner also underwent genetic testing and they do not have the disorder gene. The nurse would advise the couple that their unborn child has a _____ ­­­­percent probability of not having Huntington's Disease?

    %

    Explanation & Rationale

    Rationale: Autosomal dominant inheritance: One mutated allele is sufficient to cause disease. Heterozygous × unaffected (Hh × hh): Each child has a 50% chance to inherit h from both parents (hh, unaffected) and a 50% chance to inherit H from the affected parent (Hh, affected). Punnett square outcome: Two unaffected (hh) out of four possibilities → 50% probability of not having Huntington’s disease.

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