Calculate the 12-hour intake of the following patient: For breakfast, Mrs. Smith consumed 4 oz. of milk and 4 oz of black coffee. At 1030, she urinated 450 mL. At 1100, she received 125 mL of ampicllin IV and drank 400 mL of water. At lunch time, Mrs. Smith consumed 8 oz of water and 4 oz of apple juice. At 1300, Mrs. Smith urinated 400 mL of urine and produced 75 mL of green emesis. At 1500, Mrs. Smith consumed 7 oz of ice chips an 4 oz of jello. For dinner, she consumed 50% of her meal and 8 oz of soda and 8 oz of water. Do not provide the unit of measurement. Only provide the number.

Use 1 oz = 30 mL. Breakfast: 4 oz milk + 4 oz coffee = 8 oz = 8 × 30 = 240 mL. 1030: urine output (450 mL) — not part of intake. 1100: 125 mL IV ampicillin + 400 mL water = 525 mL. Lunch: 8 oz water + 4 oz apple juice = 12 oz = 12 × 30 = 360 mL. 1300: urine (400 mL) and emesis (75 mL) — outputs, not intake. 1500: 7 oz ice chips + 4 oz jello = 11 oz = 11 × 30 = 330 mL. Dinner: 8 oz soda + 8 oz water = 16 oz = 16 × 30 = 480 mL. (Assumed “50% of her meal” provided no additional measurable fluid.) Total intake = 240 + 525 + 360 + 330 + 480 = 1935 mL. Final Answer: 1935