How many mEq of potassium chloride are in a 100 mL solution containing 0.5 g of KCl (molecular weights: K = 39; Cl = 35.5)? Round the final answer to the nearest whole number.

Step 1 is to calculate the molecular weight (MW) of KCl MW = K (39) + Cl (35.5) 39 + 35.5 = 74.5 Result at this step = 74.5 g/mol Step 2 is to convert grams (g) to milligrams (mg) mg = 0.5 g × 1,000 0.5 × 1,000 = 500 Result at this step = 500 mg Step 3 is to calculate the milliequivalents (mEq) Formula: mEq = (mg × valence) ÷ MW Valence of KCl = 1 mEq = (500 × 1) ÷ 74.5 500 × 1 = 500 (500 ÷ 74.5) = 6.7114 Result at this step = 6.7114 mEq Step 4 is to round to the nearest whole number 6.7114 ≈ 7 Answer: 7