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    ATI Nurs 520 Pharmacology proctored Exam

    The healthcare provider orders Compazine 10 mg IM now. The concentration available is Compazine 5 mg/mL. How many mL will the patient receive?

    Explanation & Rationale

    Choice A reason: For 10 mg at 5 mg/mL: 10 ÷ 5 = 2 mL. Choice A (0.5 mL) delivers 2.5 mg (0.5 × 5), underdosing Compazine, which may fail to control nausea or psychosis, making this choice incorrect for the prescribed dose. Choice B reason: The correct volume is 10 mg ÷ 5 mg/mL = 2 mL. Choice B (4 mL) delivers 20 mg (4 × 5), overdosing Compazine, risking extrapyramidal symptoms or sedation, making this choice incorrect and potentially harmful for safe administration. Choice C reason: For 10 mg, the volume is 2 mL (10 ÷ 5). Choice C (1 mL) delivers 5 mg (1 × 5), underdosing Compazine, which could be ineffective for nausea or psychiatric symptoms, making this choice inadequate for the ordered dose. Choice D reason: Calculating 10 mg ÷ 5 mg/mL = 2 mL accurately delivers the ordered 10 mg of Compazine (prochlorperazine) for nausea or psychosis. This ensures therapeutic efficacy without overdose, aligning with safe intramuscular administration, making this the correct choice.

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