The healthcare provider prescribes a hydration IV of normal saline to run over 3 hours at 30 mL/kg for a client who is dehydrated and weighs 154 pounds. The nurse should program the infusion pump to deliver how many mL/hour? (Enter numeric value only.)

First, we need to convert the client’s weight from pounds to kilograms since the dosage is prescribed in mL/kg. We know that 1 kg is approximately 2.20462 pounds. So, Weight in kg= Weight in pounds/2.20462 ​= 154 / 2.20462 ​≈ 69.85kg The prescribed dosage is 30 mL/kg, so the total volume in mL would be: Volume in mL= Dosage per kg × Weight in kg=30mL/kg × 69.85kg ≈ 2095.5mL The medication is to be administered over 3 hours. Therefore, the rate in mL/hour would be: Rate in mL/hour = Volume in mL / Time in hours ​= 2095.5mL/3hours ​ ≈ 698.5mL/hour So, the nurse should program the infusion pump to deliver approximately 699 mL/hour.