The healthcare provider prescribes cefazolin 800 mg IM every six hours. The available vial is labeled, "Cefazolin 1 gram," and the instructions for reconstitution state, For IM use add 2.5 mL sterile water for injection to provide a total volume of 3.0 mL". Afterreconstitution, the solution contains how many mg/mL? (Enter numeric value only. If rounding is required, round to the nearest whole number.)

- To find the volume of cefazolin to administer, we need to use the formula: Volume = Dose / Concentration - First, we need to find the concentration of cefazolin after reconstitution. The label says that 1 gram of cefazolin is dissolved in 3 mL of water. To get the concentration in mg/mL, we need to multiply both the numerator and denominator by 1000: (1000 mg / 1 g) x (1 g / 3 mL) = 1000 mg / 3 mL - Next, we need to simplify the fraction by dividing both the numerator and denominator by the greatest common factor, which is 3: (1000 mg / 3) / (3 mL / 3) = 333.33 mg/mL - Now, we have the concentration of cefazolin in mg/mL. We can plug in the given dose of 800 mg into the formula: Volume = 800 mg / 333.33 mg/mL - Finally, we need to solve for the volume by dividing both sides by 333.33: Volume / 333.33 = (800 mg / 333.33 mg/mL) / 333.33 - The answer is 2.4 mL (rounded to the nearest tenth)